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2016年Sun認(rèn)證重點(diǎn)試題
Sun公司推出了Java以及Solaris技術(shù)認(rèn)證方案。對(duì)于企業(yè)而言，可以借助這項(xiàng)認(rèn)證作為招聘人才的評(píng)判標(biāo)準(zhǔn)，或是作為衡量員工技術(shù)水準(zhǔn)的依據(jù);在個(gè)人方面，通過(guò)這些認(rèn)證也可以證明個(gè)人的技術(shù)能力。下面是最新的sun認(rèn)證考試題及答案，希望能幫助到大家!
1.寫(xiě)出此程序的輸出結(jié)果.
class Test_For
{
public static void main(String[] args)
{
int i=0;
for(show('A'); show('B')&&(i<2);show('C'))
{
i++;
show('D');
}
}
public static boolean show(char ch)
{
System.out.print(ch);
return true;
}
}
2.寫(xiě)出此程序的輸出結(jié)果.
class Demo
{
public static void main(String[] args)
{
int a=3,b=8;
int c=(a>b)?a++:b++;
System.out.println("a="+a+"\tb="+b+"\tc+"+c);
int d=(a>b)?++a:++b;
System.out.println("a="+a+"\tb="+b+"\tc+"+d);
int e=(a
System.out.println("a="+a+"\tb="+b+"\tc+"+e);
int f=(a
System.out.println("a="+a+"\tb="+b+"\tc+"+f);
}
}
3.寫(xiě)出此程序的輸出結(jié)果.
class Demo
{
public static void main(String []args)
{
int i = 0, j = 5;
tp: for (;;)
{
i++;
for(;;)
if(i > j--) break tp;
}
System.out.println("i = " + i + ", j = "+ j);
}
}
4.寫(xiě)出此程序的輸出結(jié)果.
class DemoWhile_3
{
public static void main(String[] args)
{
int x=1;
while(x<10)
{
wx:while(x<7)
{
while(x<4)
{
System.out.print("A ");
x++;
break wx;
}
System.out.print("B ");
x++;
}
System.out.print("C ");
x++;
}
}
}
5.選擇正確答案:
class Test
{
public static void main(String[] args)
{
String foo=args[1];
String bar=args[2];
String baz=args[3];
}
}
d:\>java Test Red Green Blue
what is the value of baz?
A. baz has value of ""
B. baz has value of null
C. baz has value of "Red"
D. baz has value of "Blue"
E. baz has value of "Green"
F. the code does not compile
G. the program throw an exception
6.寫(xiě)出輸出結(jié)果.
class Demo
{
public static void main(String[] args)
{
show(0);
show(1);
}
public static void show(int i)
{
switch(i)
{
default:
i+=2;
case 1:
i+=1;
case 4:
i+=8;
case 2:
i+=4;
}
System.out.println("i="+i);
}
}
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